Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Connect with professionals ready to provide precise answers to your questions on our comprehensive Q&A platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

A locker combination has three nonzero digits, and digits cannot be repeated. The first two digits are 1 and 2. What is the probability that the third digit is 3?

A) [tex]\frac{7}{9}[/tex]
B) [tex]\frac{1}{3}[/tex]
C) [tex]\frac{1}{6}[/tex]
D) [tex]\frac{1}{7}[/tex]


Sagot :

To determine the probability that the third digit in the locker combination is 3, let's analyze the situation step by step.

1. Identify the available digits: The combination already uses the digits 1 and 2, so they can't be used for the third position. The available digits for the third position are: 3, 4, 5, 6, 7, 8, and 9.

2. Count the remaining digits: There are 7 possible digits remaining (3 through 9).

3. Determine the number of favorable outcomes: We're interested in the specific case where the third digit is 3. Hence, there is only 1 favorable outcome (where the third digit is 3).

4. Calculate the probability: The probability is given by the ratio of the number of favorable outcomes to the total number of possible outcomes. Therefore, the probability is:
[tex]\[ \text{Probability} = \frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}} = \frac{1}{7} \][/tex]

Thus, the probability that the third digit is 3 is \( \frac{1}{7} \).

So the correct answer is:
D) [tex]\( \frac{1}{7} \)[/tex]