To determine the width of each class for the frequency distribution given, follow these steps:
1. Identify the Class Boundaries:
Look at any class interval from the table. The boundaries are the values at the start and the end of the interval. Let's use the first interval, [tex]$80.0-110.9$[/tex].
2. Calculate the Class Width:
Subtract the lower boundary from the upper boundary.
[tex]$[tex]$ \text{Upper boundary} - \text{Lower boundary} = 110.9 - 80.0 $[/tex]$[/tex]
3. Compute the Difference:
[tex]$[tex]$ 110.9 - 80.0 = 30.9 $[/tex]$[/tex]
4. Round to the Nearest Whole Number:
Round [tex]$30.9$[/tex] to the nearest whole number, which gives:
[tex]$[tex]$ 31 $[/tex]$[/tex]
So, the width of each class, rounded to the nearest whole number, is \( 31 \).
Therefore, the correct answer is:
[tex]\[ \boxed{31} \][/tex]
