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Sagot :
To find the value of \( d_1 \) for different values of \( d_2 \) and \( A \), we start with the given formula for the area of a rhombus:
[tex]\[ A = \frac{1}{2} d_1 d_2 \][/tex]
We need to rearrange this equation to solve for \( d_1 \). First, let's isolate \( d_1 \) on one side of the equation.
1. Start with the area formula:
[tex]\[ A = \frac{1}{2} d_1 d_2 \][/tex]
2. Multiply both sides of the equation by 2 to get rid of the fraction:
[tex]\[ 2A = d_1 d_2 \][/tex]
3. Now, divide both sides by \( d_2 \) to solve for \( d_1 \):
[tex]\[ d_1 = \frac{2A}{d_2} \][/tex]
Therefore, the equation to find \( d_1 \) when \( d_2 \) and \( A \) are given is:
[tex]\[ d_1 = \frac{2A}{d_2} \][/tex]
Hence, the correct choice is:
[tex]\[ \boxed{B} \][/tex]
[tex]\[ A = \frac{1}{2} d_1 d_2 \][/tex]
We need to rearrange this equation to solve for \( d_1 \). First, let's isolate \( d_1 \) on one side of the equation.
1. Start with the area formula:
[tex]\[ A = \frac{1}{2} d_1 d_2 \][/tex]
2. Multiply both sides of the equation by 2 to get rid of the fraction:
[tex]\[ 2A = d_1 d_2 \][/tex]
3. Now, divide both sides by \( d_2 \) to solve for \( d_1 \):
[tex]\[ d_1 = \frac{2A}{d_2} \][/tex]
Therefore, the equation to find \( d_1 \) when \( d_2 \) and \( A \) are given is:
[tex]\[ d_1 = \frac{2A}{d_2} \][/tex]
Hence, the correct choice is:
[tex]\[ \boxed{B} \][/tex]
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