To solve the equation \( 3x + 2 = x + 28 \):
1. Isolate the x-terms: We start by moving the terms involving \( x \) to one side of the equation. To do this, subtract \( x \) from both sides:
[tex]\[
3x + 2 - x = x + 28 - x
\][/tex]
Simplifying gives:
[tex]\[
2x + 2 = 28
\][/tex]
The coefficient of \( x \) on the left side is now \( 2 \).
2. Isolate the constant terms: Next, we move the constant term on the left side to the right side by subtracting \( 2 \) from both sides:
[tex]\[
2x + 2 - 2 = 28 - 2
\][/tex]
Simplifying gives:
[tex]\[
2x = 26
\][/tex]
3. Solve for \( x \): Finally, to find the value of \( x \), divide both sides of the equation by \( 2 \):
[tex]\[
x = \frac{26}{2}
\][/tex]
Which simplifies to:
[tex]\[
x = 13
\][/tex]
Therefore, the solution to the equation [tex]\( 3x + 2 = x + 28 \)[/tex] is [tex]\( x = 13 \)[/tex].
