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Place the elements in each set in order of increasing electronegativity:

a. [tex]$Ba, Ca, Sr$[/tex]:

b. [tex]$S, O, Se$[/tex]:

c. [tex]$Ge, Si, C$[/tex]:

d. [tex]$Cl, S, P$[/tex]:

Sagot :

GinnyAnswer
Let's arrange the elements in each set by increasing electronegativity:

### Set a: \( \text{Ba}, \text{Ca}, \text{Sr} \)
To place these elements in order of increasing electronegativity, we need to compare their respective electronegativity values.
\- For Barium (Ba), the electronegativity is 0.89.
\- For Calcium (Ca), the electronegativity is 1.00.
\- For Strontium (Sr), the electronegativity is 0.95.

Arranging them in increasing order:
[tex]\[ \text{Ba}, \text{Sr}, \text{Ca} \][/tex]

### Set b: \( \text{S}, \text{O}, \text{Se} \)
We will do the same comparison here for sulfur, oxygen, and selenium.
\- For Sulfur (S), the electronegativity is 2.58.
\- For Oxygen (O), the electronegativity is 3.44.
\- For Selenium (Se), the electronegativity is 2.55.

Arranging them in increasing order:
[tex]\[ \text{Se}, \text{S}, \text{O} \][/tex]

### Set c: \( \text{Ge}, \text{Si}, \text{C} \)
Next, for germanium, silicon, and carbon:
\- For Germanium (Ge), the electronegativity is 2.01.
\- For Silicon (Si), the electronegativity is 1.90.
\- For Carbon (C), the electronegativity is 2.55.

Arranging them in increasing order:
[tex]\[ \text{Si}, \text{Ge}, \text{C} \][/tex]

### Set d: \( \text{Cl}, \text{S}, \text{P} \)
Finally, for chlorine, sulfur, and phosphorus:
\- For Chlorine (Cl), the electronegativity is 3.16.
\- For Sulfur (S), the electronegativity is 2.58.
\- For Phosphorus (P), the electronegativity is 2.19.

Arranging them in increasing order:
[tex]\[ \text{P}, \text{S}, \text{Cl} \][/tex]

### Final Order for Each Set:
a. \( \text{Ba}, \text{Sr}, \text{Ca} \)

b. \( \text{Se}, \text{S}, \text{O} \)

c. \( \text{Si}, \text{Ge}, \text{C} \)

d. [tex]\( \text{P}, \text{S}, \text{Cl} \)[/tex]
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