Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

Given the functions:

[tex]\[
\begin{array}{l}
g(a) = 3a + 4 \\
h(a) = a^2 + a
\end{array}
\][/tex]

Find [tex]\(\left(\frac{g}{h}\right)\left(\frac{a}{2}\right)\)[/tex].


Sagot :

To find \( \left( \frac{g}{h} \right) \left( \frac{a}{2} \right)\), we'll proceed by evaluating the given functions \(g(a)\) and \(h(a)\) at a specific value of \(a\). Here's the step-by-step process:

1. Define the functions \( g(a) \) and \( h(a) \):
- \( g(a) = 3a + 4 \)
- \( h(a) = a^2 + a \)

2. Substitute \(\frac{a}{2}\) into the functions \( g \) and \( h \):

- Evaluate \( g \left( \frac{a}{2} \right) \):
[tex]\[ g \left( \frac{a}{2} \right) = 3 \left( \frac{a}{2} \right) + 4 \][/tex]
Simplifying this,
[tex]\[ g \left( \frac{a}{2} \right) = \frac{3a}{2} + 4 \][/tex]
Substituting \( a = 1 \),
[tex]\[ g \left( \frac{1}{2} \right) = \frac{3 \cdot 0.5}{2} + 4 = 1.5 + 4 = 5.5 \][/tex]

- Evaluate \( h \left( \frac{a}{2} \right) \):
[tex]\[ h \left( \frac{a}{2} \right) = \left( \frac{a}{2} \right)^2 + \frac{a}{2} \][/tex]
Simplifying this,
[tex]\[ h \left( \frac{a}{2} \right) = \left( \frac{a^2}{4} \right) + \left( \frac{a}{2} \right) \][/tex]
Substituting \( a = 1 \),
[tex]\[ h \left( \frac{1}{2} \right) = \left( \frac{0.5^2}{4} \right) + \left( \frac{0.5}{2} \right) = 0.25 + 0.5 = 0.75 \][/tex]

3. Calculate \(\left( \frac{g}{h} \right) \left( \frac{a}{2} \right)\):
[tex]\[ \left( \frac{g}{h} \right) \left( \frac{a}{2} \right) = \frac{g \left( \frac{a}{2} \right)}{h \left( \frac{a}{2} \right)} \][/tex]
Substituting the values we found,
[tex]\[ \left( \frac{g}{h} \right) \left( \frac{1}{2} \right) = \frac{5.5}{0.75} = 7.\overline{3} \][/tex]

Therefore, the result is:
[tex]\[(5.5, 0.75, 7.333333333333333)\][/tex]
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.