Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Explore thousands of questions and answers from a knowledgeable community of experts ready to help you find solutions. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.

Given the functions:

[tex]\[
\begin{array}{l}
g(a) = 3a + 4 \\
h(a) = a^2 + a
\end{array}
\][/tex]

Find [tex]\(\left(\frac{g}{h}\right)\left(\frac{a}{2}\right)\)[/tex].


Sagot :

To find \( \left( \frac{g}{h} \right) \left( \frac{a}{2} \right)\), we'll proceed by evaluating the given functions \(g(a)\) and \(h(a)\) at a specific value of \(a\). Here's the step-by-step process:

1. Define the functions \( g(a) \) and \( h(a) \):
- \( g(a) = 3a + 4 \)
- \( h(a) = a^2 + a \)

2. Substitute \(\frac{a}{2}\) into the functions \( g \) and \( h \):

- Evaluate \( g \left( \frac{a}{2} \right) \):
[tex]\[ g \left( \frac{a}{2} \right) = 3 \left( \frac{a}{2} \right) + 4 \][/tex]
Simplifying this,
[tex]\[ g \left( \frac{a}{2} \right) = \frac{3a}{2} + 4 \][/tex]
Substituting \( a = 1 \),
[tex]\[ g \left( \frac{1}{2} \right) = \frac{3 \cdot 0.5}{2} + 4 = 1.5 + 4 = 5.5 \][/tex]

- Evaluate \( h \left( \frac{a}{2} \right) \):
[tex]\[ h \left( \frac{a}{2} \right) = \left( \frac{a}{2} \right)^2 + \frac{a}{2} \][/tex]
Simplifying this,
[tex]\[ h \left( \frac{a}{2} \right) = \left( \frac{a^2}{4} \right) + \left( \frac{a}{2} \right) \][/tex]
Substituting \( a = 1 \),
[tex]\[ h \left( \frac{1}{2} \right) = \left( \frac{0.5^2}{4} \right) + \left( \frac{0.5}{2} \right) = 0.25 + 0.5 = 0.75 \][/tex]

3. Calculate \(\left( \frac{g}{h} \right) \left( \frac{a}{2} \right)\):
[tex]\[ \left( \frac{g}{h} \right) \left( \frac{a}{2} \right) = \frac{g \left( \frac{a}{2} \right)}{h \left( \frac{a}{2} \right)} \][/tex]
Substituting the values we found,
[tex]\[ \left( \frac{g}{h} \right) \left( \frac{1}{2} \right) = \frac{5.5}{0.75} = 7.\overline{3} \][/tex]

Therefore, the result is:
[tex]\[(5.5, 0.75, 7.333333333333333)\][/tex]
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.