Certainly! To find the probability that a given light bulb lasts between 525 and 750 hours for a normal distribution with a mean (μ) of 750 hours and a standard deviation (σ) of 75 hours, we can follow these steps:
1. Determine the z-scores for the lower and upper bounds:
- The z-score formula is given by \( z = \frac{(X - \mu)}{\sigma} \).
- For the lower bound (525 hours):
[tex]\[
z_{\text{lower}} = \frac{(525 - 750)}{75} = \frac{-225}{75} = -3
\][/tex]
- For the upper bound (750 hours):
[tex]\[
z_{\text{upper}} = \frac{(750 - 750)}{75} = \frac{0}{75} = 0
\][/tex]
2. Use the cumulative distribution function (CDF) to find the probabilities associated with these z-scores:
- The CDF of a standard normal distribution gives the probability that a value is less than or equal to a given z-score.
- For \( z_{\text{lower}} = -3 \):
[tex]\[
P(Z \leq -3) = 0.00135
\][/tex]
- For \( z_{\text{upper}} = 0 \):
[tex]\[
P(Z \leq 0) = 0.5
\][/tex]
3. Calculate the probability that a light bulb's lifetime falls between the two z-scores:
- This probability is the difference between the CDF values for the upper and lower z-scores:
[tex]\[
P(525 \leq X \leq 750) = P(Z \leq 0) - P(Z \leq -3) = 0.5 - 0.00135 = 0.49865
\][/tex]
So, the probability that a given light bulb lasts between 525 and 750 hours is approximately [tex]\( 0.49865 \)[/tex], or [tex]\( 49.865\% \)[/tex].
