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Taking [tex]\sqrt{2}=1.414[/tex] and [tex]\pi=3.141[/tex], evaluate [tex]\frac{1}{\sqrt{2}}+\pi[/tex] up to three decimal places.

Sagot :

GinnyAnswer
Sure, let's solve the given problem step by step.

Given values:
[tex]\[ \sqrt{2} = 1.414 \quad \text{and} \quad \pi = 3.141 \][/tex]

We need to evaluate the expression:
[tex]\[ \frac{1}{\sqrt{2}} + \pi \][/tex]

First, we need to calculate \(\frac{1}{\sqrt{2}}\) using the given value for \(\sqrt{2}\):
[tex]\[ \frac{1}{\sqrt{2}} = \frac{1}{1.414} \][/tex]

Dividing 1 by 1.414:
[tex]\[ \frac{1}{1.414} \approx 0.707 \][/tex]

Next, we add the value of \(\pi\) to this result:
[tex]\[ 0.707 + 3.141 \][/tex]

Adding these values together:
[tex]\[ 0.707 + 3.141 = 3.848 \][/tex]

Therefore, the value of the expression \(\frac{1}{\sqrt{2}} + \pi\) rounded to three decimal places is:
[tex]\[ \boxed{3.848} \][/tex]
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