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The value of [tex]\sqrt[3]{x^{10}}[/tex], when [tex]x=-2[/tex], can be written in simplest form as [tex]a \sqrt[3]{b}[/tex], where

[tex]\[ a = \boxed{\phantom{0}} \][/tex]
[tex]\[ b = \boxed{\phantom{0}} \][/tex]


Sagot :

To determine the simplest form of \(\sqrt[3]{x^{10}}\) when \(x = -2\), let's work through the problem step by step:

1. Start with the given value of \(x\):
[tex]\[ x = -2 \][/tex]

2. Calculate \(x^{10}\):
[tex]\[ x^{10} = (-2)^{10} \][/tex]
When a negative number is raised to an even power, the result is positive. Therefore:
[tex]\[ (-2)^{10} = 1024 \][/tex]

3. Find the cube root of \(x^{10}\):
[tex]\[ \sqrt[3]{(-2)^{10}} = \sqrt[3]{1024} \][/tex]

4. Express \(\sqrt[3]{1024}\) in the form \(a \sqrt[3]{b}\):
We need to find an \(a\) and a \(b\) such that:
[tex]\[ \sqrt[3]{1024} = a \sqrt[3]{b} \][/tex]
Notice that 1024 is a perfect power of 2:
[tex]\[ 1024 = 2^{10} \][/tex]
Now take the cube root of \(2^{10}\):
[tex]\[ \sqrt[3]{1024} = \sqrt[3]{2^{10}} = 2^{10/3} \][/tex]

To express this as \(a \sqrt[3]{b}\), decompose \(2^{10/3}\):
[tex]\[ 2^{10/3} = 2^{3 + 1/3} = 2^3 \cdot 2^{1/3} \][/tex]
Simplify this:
[tex]\[ 2^3 \cdot 2^{1/3} = 8 \cdot \sqrt[3]{2} \][/tex]

5. Identify \(a\) and \(b\):
By comparing the simplified expression with the form \(a \sqrt[3]{b}\), we see that:
[tex]\[ a = 8 \quad \text{and} \quad b = 2 \][/tex]

Therefore, \(\sqrt[3]{x^{10}}\) when \(x = -2\) can be written in simplest form as:
[tex]\[ 8 \sqrt[3]{2} \][/tex]
So, the values of \(a\) and \(b\) are:
[tex]\[ a = 8 \quad \text{and} \quad b = 2 \][/tex]