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An eagle carries a fish up [tex]50 \, m[/tex] into the sky using [tex]90 \, N[/tex] of force. How much work did the eagle do on the fish? (Work [tex]W = Fd[/tex])

A. [tex]40 \, J[/tex]
B. [tex]59 \, J[/tex]
C. [tex]140 \, J[/tex]
D. [tex]4500 \, J[/tex]

Sagot :

GinnyAnswer
To determine how much work the eagle did in carrying the fish up into the sky, we can use the formula for work:

[tex]\[ W = F \cdot d \][/tex]

where:
- \( W \) is the work done,
- \( F \) is the force applied,
- \( d \) is the distance over which the force is applied.

Given data:
- The force (\( F \)) the eagle used is \( 90 \, \text{N} \).
- The distance (\( d \)) the eagle flew upward is \( 50 \, \text{m} \).

We substitute these values into the formula:

[tex]\[ W = 90 \, \text{N} \times 50 \, \text{m} \][/tex]

Multiplying these together:

[tex]\[ W = 4500 \, \text{J} \][/tex]

So, the work done by the eagle is \( 4500 \, \text{J} \).

The correct answer from the given options is:
[tex]\[ 4500 \, \text{J} \][/tex]
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