To find the probability that a randomly selected tree in the forest has a height greater than or equal to 37 meters, we can use the properties of the normal distribution and the provided standard normal table.
1. Identify the Given Information:
- Mean height, \(\mu\) = 25 meters
- Standard deviation, \(\sigma\) = 6 meters
- Selected height, \(X = 37\) meters
2. Calculate the Z-Score:
The Z-score represents the number of standard deviations a given value is from the mean. The formula for the Z-score is:
[tex]\[
Z = \frac{X - \mu}{\sigma}
\][/tex]
Substituting the given values:
[tex]\[
Z = \frac{37 - 25}{6} = \frac{12}{6} = 2.0
\][/tex]
3. Find the Probability Corresponding to the Z-Score:
Using the standard normal distribution table, we look up the probability for \(Z = 2.0\). According to the provided table, the probability that a standard normal variable is less than or equal to 2.0 is 0.9772.
4. Calculate the Probability for Greater Heights:
The probability that a randomly selected tree has a height greater than or equal to 37 meters is:
[tex]\[
P(X \geq 37) = 1 - P(Z \leq 2.0)
\][/tex]
Using the value from the table:
[tex]\[
P(X \geq 37) = 1 - 0.9772 = 0.0228
\][/tex]
Thus, the probability that a randomly selected tree in the forest has a height greater than or equal to 37 meters is \(0.0228\) or \(2.3\%\).
Answer: [tex]\(2.3\%\)[/tex]
