Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

What is the slope of a line perpendicular to the line [tex]y = -\frac{1}{2} x - 68[/tex]?

A. [tex]\frac{1}{2}[/tex]

B. 6

C. [tex]\frac{1}{6}[/tex]

D. 2


Sagot :

To solve this problem, we need to find the slope of a line that is perpendicular to the given line \( y = -\frac{1}{2}x - 68 \).

1. Identify the slope of the given line:
The equation of the line is given in slope-intercept form \( y = mx + b \), where \( m \) is the slope.
For the line \( y = -\frac{1}{2}x - 68 \), the slope \( m \) is \( -\frac{1}{2} \).

2. Find the negative reciprocal:
The slope of a line perpendicular to another line is the negative reciprocal of the given slope.
- The reciprocal of \( -\frac{1}{2} \) is \( -2 \) (reciprocal changes the numerator and denominator and flips the sign).
- The negative reciprocal of \( -\frac{1}{2} \) is therefore \( 2 \).

So, the slope of the perpendicular line is \( 2 \).

Given the multiple choices, the correct answer is:
d.) [tex]\( 2 \)[/tex]