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How many grams of Cl2 will be produced along with 250.0 kJ of heat in the following reaction? PCl5(g) + 87.9 kJ PCl3(g) + Cl2(g)
A.
2.844 grams
B.
87.90 grams
C.
101.0 grams
D.
201.9 grams
E.
250.0 grams


Sagot :

Answer:201.9 grams

Explanation:

To determine how many grams of Cl₂ will be produced along with 250.0 kJ of heat in the given reaction, we need to follow these steps:

1. **Understand the reaction and its enthalpy change:**

  The given reaction is:

  \[

  \text{PCl}_5(g) + 87.9 \, \text{kJ} \rightarrow \text{PCl}_3(g) + \text{Cl}_2(g)

  \]

  This indicates that 87.9 kJ of heat is required to produce 1 mole of Cl₂.

2. **Calculate the number of moles of Cl₂ produced with 250.0 kJ of heat:**

  Using the given enthalpy change, we can set up a proportion to find the moles of Cl₂ produced by 250.0 kJ of heat:

  \[

  \frac{1 \text{ mole of Cl}_2}{87.9 \, \text{kJ}} = \frac{n \, \text{moles of Cl}_2}{250.0 \, \text{kJ}}

  \]

  Solving for \(n\):

  \[

  n = \frac{250.0 \, \text{kJ}}{87.9 \, \text{kJ/mole}}

  \]

  \[

  n \approx 2.844 \, \text{moles of Cl}_2

  \]

3. **Convert moles of Cl₂ to grams:**

  The molar mass of Cl₂ is calculated as follows:

  - The atomic mass of Cl (chlorine) is approximately 35.5 g/mol.

  - Since Cl₂ consists of two chlorine atoms, its molar mass is \( 2 \times 35.5 \, \text{g/mol} = 71.0 \, \text{g/mol} \).

  Now, we convert moles to grams:

  \[

  \text{Mass of Cl}_2 = n \times \text{molar mass of Cl}_2

  \]

  \[

  \text{Mass of Cl}_2 = 2.844 \, \text{moles} \times 71.0 \, \text{g/mol}

  \]

  \[

  \text{Mass of Cl}_2 \approx 201.964 \, \text{g}

  \]

Therefore, approximately 201.964 grams of Cl₂ will be produced along with 250.0 kJ of heat in the given reaction.

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