Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Our platform connects you with professionals ready to provide precise answers to all your questions in various areas of expertise. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
Answer:201.9 grams
Explanation:
To determine how many grams of Cl₂ will be produced along with 250.0 kJ of heat in the given reaction, we need to follow these steps:
1. **Understand the reaction and its enthalpy change:**
The given reaction is:
\[
\text{PCl}_5(g) + 87.9 \, \text{kJ} \rightarrow \text{PCl}_3(g) + \text{Cl}_2(g)
\]
This indicates that 87.9 kJ of heat is required to produce 1 mole of Cl₂.
2. **Calculate the number of moles of Cl₂ produced with 250.0 kJ of heat:**
Using the given enthalpy change, we can set up a proportion to find the moles of Cl₂ produced by 250.0 kJ of heat:
\[
\frac{1 \text{ mole of Cl}_2}{87.9 \, \text{kJ}} = \frac{n \, \text{moles of Cl}_2}{250.0 \, \text{kJ}}
\]
Solving for \(n\):
\[
n = \frac{250.0 \, \text{kJ}}{87.9 \, \text{kJ/mole}}
\]
\[
n \approx 2.844 \, \text{moles of Cl}_2
\]
3. **Convert moles of Cl₂ to grams:**
The molar mass of Cl₂ is calculated as follows:
- The atomic mass of Cl (chlorine) is approximately 35.5 g/mol.
- Since Cl₂ consists of two chlorine atoms, its molar mass is \( 2 \times 35.5 \, \text{g/mol} = 71.0 \, \text{g/mol} \).
Now, we convert moles to grams:
\[
\text{Mass of Cl}_2 = n \times \text{molar mass of Cl}_2
\]
\[
\text{Mass of Cl}_2 = 2.844 \, \text{moles} \times 71.0 \, \text{g/mol}
\]
\[
\text{Mass of Cl}_2 \approx 201.964 \, \text{g}
\]
Therefore, approximately 201.964 grams of Cl₂ will be produced along with 250.0 kJ of heat in the given reaction.
Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.
