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Complete the table for the function.

[tex]\[
f(x) = \sqrt{x + 3} + 4
\][/tex]

[tex]\[
\begin{array}{r|r}
x & y \\
\hline
-3 & {[?]} \\
-2 & \\
1 & \\
6 &
\end{array}
\][/tex]

Sagot :

GinnyAnswer
To complete the table for the function \( f(x) = \sqrt{x+3} + 4 \), let's evaluate the function at each given \( x \) value step-by-step.

1. For \( x = -3 \):
[tex]\[ f(-3) = \sqrt{-3 + 3} + 4 = \sqrt{0} + 4 = 0 + 4 = 4 \][/tex]

2. For \( x = -2 \):
[tex]\[ f(-2) = \sqrt{-2 + 3} + 4 = \sqrt{1} + 4 = 1 + 4 = 5 \][/tex]

3. For \( x = 1 \):
[tex]\[ f(1) = \sqrt{1 + 3} + 4 = \sqrt{4} + 4 = 2 + 4 = 6 \][/tex]

4. For \( x = 6 \):
[tex]\[ f(6) = \sqrt{6 + 3} + 4 = \sqrt{9} + 4 = 3 + 4 = 7 \][/tex]

Now, let's fill in the completed table with the calculated \( y \)-values.
[tex]\[ \begin{array}{r|r} x & y \\ \hline -3 & 4.0 \\ -2 & 5.0 \\ 1 & 6.0 \\ 6 & 7.0 \\ \end{array} \][/tex]
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