Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Get detailed answers to your questions from a community of experts dedicated to providing accurate information. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.
Sagot :
To analyze the motion of the ball thrown vertically upwards from position P, we can break down the question into two main components: net displacement and total distance traveled.
### Net Displacement
1. Net Displacement Definition: Displacement is a vector quantity that refers to the change in position of an object. It is calculated as the straight-line distance from the initial position to the final position, along with a specified direction.
2. Initial and Final Positions: In this scenario, the ball starts at position P, rises to the highest point Q, and eventually returns back to position P. Since the ball returns to its starting point, the initial and final positions are the same.
3. Calculation: The change in position (displacement) is zero because the ball ends up exactly where it started.
[tex]\[ \text{Net Displacement} = 0 \text{ units} \][/tex]
### Total Distance Traveled
1. Distance Definition: Distance is a scalar quantity that refers to the total path length traveled by an object irrespective of direction. It's always positive or zero, never negative.
2. Path of the Ball: The ball moves from position P to the highest point Q and then back from Q to P. The movement consists of two parts:
- The distance from P to Q (upwards).
- The distance from Q to P (downwards).
3. Calculation:
- Let the height of the highest point Q from position P be H.
- Therefore, the ball travels a distance H upwards.
- It then travels the same distance H downwards to return to position P.
- The total distance traveled is the sum of these two distances:
[tex]\[ \text{Total Distance} = H (\text{up}) + H (\text{down}) = 2H \][/tex]
4. Example: If we assume the height \(H\) the ball reaches from position P is 10 units, then:
[tex]\[ \text{Total Distance} = 2 \times 10 = 20 \text{ units} \][/tex]
### Conclusion
- Net Displacement: The net displacement of the ball is \(0\) units.
- Total Distance Traveled: The total distance traveled by the ball is \(20\) units.
These are the results of the ball's motion when thrown vertically upwards from position P, rising to the highest point Q, and then returning back to position P.
### Net Displacement
1. Net Displacement Definition: Displacement is a vector quantity that refers to the change in position of an object. It is calculated as the straight-line distance from the initial position to the final position, along with a specified direction.
2. Initial and Final Positions: In this scenario, the ball starts at position P, rises to the highest point Q, and eventually returns back to position P. Since the ball returns to its starting point, the initial and final positions are the same.
3. Calculation: The change in position (displacement) is zero because the ball ends up exactly where it started.
[tex]\[ \text{Net Displacement} = 0 \text{ units} \][/tex]
### Total Distance Traveled
1. Distance Definition: Distance is a scalar quantity that refers to the total path length traveled by an object irrespective of direction. It's always positive or zero, never negative.
2. Path of the Ball: The ball moves from position P to the highest point Q and then back from Q to P. The movement consists of two parts:
- The distance from P to Q (upwards).
- The distance from Q to P (downwards).
3. Calculation:
- Let the height of the highest point Q from position P be H.
- Therefore, the ball travels a distance H upwards.
- It then travels the same distance H downwards to return to position P.
- The total distance traveled is the sum of these two distances:
[tex]\[ \text{Total Distance} = H (\text{up}) + H (\text{down}) = 2H \][/tex]
4. Example: If we assume the height \(H\) the ball reaches from position P is 10 units, then:
[tex]\[ \text{Total Distance} = 2 \times 10 = 20 \text{ units} \][/tex]
### Conclusion
- Net Displacement: The net displacement of the ball is \(0\) units.
- Total Distance Traveled: The total distance traveled by the ball is \(20\) units.
These are the results of the ball's motion when thrown vertically upwards from position P, rising to the highest point Q, and then returning back to position P.
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.