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Sagot :
Sure, let's solve the equation step-by-step:
Given equation:
[tex]\[ 2(2c + 9) = c \][/tex]
First, distribute the 2 on the left side of the equation:
[tex]\[ 2 \cdot 2c + 2 \cdot 9 = c \][/tex]
[tex]\[ 4c + 18 = c \][/tex]
Next, we want to move the term involving \( c \) on the right side to the left side of the equation to combine like terms:
[tex]\[ 4c + 18 - c = 0 \][/tex]
Simplify the left side:
[tex]\[ 3c + 18 = 0 \][/tex]
Now, isolate the term involving \( c \) by moving the constant term to the right side:
[tex]\[ 3c = -18 \][/tex]
Finally, solve for \( c \) by dividing both sides of the equation by 3:
[tex]\[ c = \frac{-18}{3} \][/tex]
[tex]\[ c = -6 \][/tex]
Thus, the solution is:
[tex]\[ c = -6 \][/tex]
Given equation:
[tex]\[ 2(2c + 9) = c \][/tex]
First, distribute the 2 on the left side of the equation:
[tex]\[ 2 \cdot 2c + 2 \cdot 9 = c \][/tex]
[tex]\[ 4c + 18 = c \][/tex]
Next, we want to move the term involving \( c \) on the right side to the left side of the equation to combine like terms:
[tex]\[ 4c + 18 - c = 0 \][/tex]
Simplify the left side:
[tex]\[ 3c + 18 = 0 \][/tex]
Now, isolate the term involving \( c \) by moving the constant term to the right side:
[tex]\[ 3c = -18 \][/tex]
Finally, solve for \( c \) by dividing both sides of the equation by 3:
[tex]\[ c = \frac{-18}{3} \][/tex]
[tex]\[ c = -6 \][/tex]
Thus, the solution is:
[tex]\[ c = -6 \][/tex]
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