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Solve for [tex]$x$[/tex].

[tex]\[
\begin{array}{c}
4x + 1 = 3x - 2 \\
x = [?]
\end{array}
\][/tex]

Sagot :

GinnyAnswer
To solve for \( x \) in the equation \( 4x + 1 = 3x - 2 \), we can follow these steps:

1. Move all terms involving \( x \) to one side of the equation and all the constant terms to the other side. This helps in isolating \( x \).

Start by subtracting \( 3x \) from both sides of the equation:
[tex]\[ 4x + 1 - 3x = 3x - 2 - 3x \][/tex]
Simplifying both sides gives us:
[tex]\[ 4x - 3x + 1 = -2 \][/tex]

2. Combine the \( x \) terms on the left side of the equation:
[tex]\[ x + 1 = -2 \][/tex]

3. Isolate the variable \( x \) by moving the constant term to the other side. Subtract 1 from both sides:
[tex]\[ x + 1 - 1 = -2 - 1 \][/tex]
Simplifying this gives:
[tex]\[ x = -3 \][/tex]

Thus, the solution to the equation \( 4x + 1 = 3x - 2 \) is:
[tex]\[ x = -3 \][/tex]
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