Answered

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Sagot :

mathstudent55

Answer:

[tex] 4x^2\sqrt{2x} [/tex]

Step-by-step explanation:

[tex] \sqrt{32x^5} = \sqrt{16 \times 2 \times x^4 \times x} = \sqrt{4^2 \times 2 \times (x^2)^2 \times x} = 4x^2\sqrt{2x} [/tex]

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