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Pls help for points!!!!
Write a quadratic equation to match the relationship given in each table.

Pls Help For Points Write A Quadratic Equation To Match The Relationship Given In Each Table class=

Sagot :

Answer:

  y = x² +9x +4

Step-by-step explanation:

You want the quadratic equation that describes the values in the table.

  • x = -2, -1, 0
  • y = -10, -4, 4

Regression

We like to use the quadratic regression function of a calculator for problems like this. As the attachment shows, using the first three points in the table gives the quadratic function ...

  y = x² +9x +4

Differences

There are some relatively simple steps you can take to determine the coefficients of the quadratic function y = ax²+bx+c "by hand."

  1. Form first differences and second differences of sequential values in the table.
    Here, the x-values are spaced 1 unit apart. This is ideal for using differences to find the quadratic coefficients. The first differences are ...
      -4-(-10) = 6, 4-(-4) = 8, 10, 12
    The second differences are the differences of these:
      8-6 = 2, 2, 2
    The "a" coefficient in the equation is half the second difference: 2/2 = 1.
  2. Using the coefficient just found, subtract ax² from each table value, and find the first differences of the resulting values.
      -10-(-2)² = -14, -4-(-1)² = -5, 4-0² = 4, ...
    The differences of these are ...
      -5-(-14) = 9, 4-(-5) = 9, ...
    The "b" coefficient is this first difference: 9.
  3. Determine the "c" coefficient by subtracting ax²+bx from the table values:
      -10 -((-2)²+9(-2)) = -10-(-14) = 4
    The "c" coefficient is this value. (It is also the value of y where x=0, which happens to be in this table.)

The quadratic equation found this way is ...

  y = x² +9x +4

__

Additional comment

You may notice that this method using differences can be automated by a spreadsheet. It only needs 3 ordered pairs with sequential x-values to determine the coefficients of the quadratic. The regression calculator can use non-sequential x-values.

In general, you can use any three (x, y) pairs to compute the coefficients a, b, c. Put the x- and y-values into the equation ax² +bx +c = y, and you will get three linear equations in a, b, c that can be solved in any of the usual ways.

If the second differences are not constant, the relation is not quadratic.

View image sqdancefan

Answer:

y = x² + 9x + 4

Step-by-step explanation:

Please find the attached.

View image olumideolawoyin
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