Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Get detailed and accurate answers to your questions from a community of experts on our comprehensive Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
To determine the domain of the function \( h(x) = \frac{9x}{x(x^2 - 36)} \), we need to find where the function is undefined. The function is undefined wherever the denominator is zero, as division by zero is not possible.
First, let's rewrite the denominator to find its roots:
[tex]\[ x(x^2 - 36) \][/tex]
We notice that the term \( x^2 - 36 \) can be factored further:
[tex]\[ x(x^2 - 36) = x(x - 6)(x + 6) \][/tex]
The function is undefined when any factor of the denominator equals zero. We solve each factor set equal to zero:
1. \( x = 0 \)
2. \( x - 6 = 0 \implies x = 6 \)
3. \( x + 6 = 0 \implies x = -6 \)
So, the function is undefined at \( x = 0 \), \( x = 6 \), and \( x = -6 \).
Therefore, the domain of the function \( h(x) \) includes all real numbers except \( x = 0 \), \( x = 6 \), and \( x = -6 \).
This corresponds to the option:
[tex]\[ B. \{x \mid x \neq \pm 6, x \neq 0\} \][/tex]
Thus, the best answer is:
[tex]\[ \boxed{B} \][/tex]
First, let's rewrite the denominator to find its roots:
[tex]\[ x(x^2 - 36) \][/tex]
We notice that the term \( x^2 - 36 \) can be factored further:
[tex]\[ x(x^2 - 36) = x(x - 6)(x + 6) \][/tex]
The function is undefined when any factor of the denominator equals zero. We solve each factor set equal to zero:
1. \( x = 0 \)
2. \( x - 6 = 0 \implies x = 6 \)
3. \( x + 6 = 0 \implies x = -6 \)
So, the function is undefined at \( x = 0 \), \( x = 6 \), and \( x = -6 \).
Therefore, the domain of the function \( h(x) \) includes all real numbers except \( x = 0 \), \( x = 6 \), and \( x = -6 \).
This corresponds to the option:
[tex]\[ B. \{x \mid x \neq \pm 6, x \neq 0\} \][/tex]
Thus, the best answer is:
[tex]\[ \boxed{B} \][/tex]
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.