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Sagot :
Answer:
[tex]y+3=2(x-2)[/tex]
Step-by-step explanation:
Pre-Solving
We are given that an equation of the line has a slope (m) of 2 and passes through the point (2, -3).
We want to write the equation of this line in point-slope form. Point-slope form is given as [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1 ,y_1)[/tex] is a point.
Solving
Substitute the values we are given into the equation.
Starting with the slope, substitute 2 for m.
[tex]y-y_1=2(x-x_1)[/tex]
Now, substitute 2 as [tex]x_1[/tex] and -3 as [tex]y_1[/tex].
[tex]y--3=2(x-2)[/tex]
This can be simplified to become:
[tex]y+3=2(x-2)[/tex]
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