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The equation of the line that passes through point (2, -3) and has a slope of 2, in point slope form is: a.y-2=2(x 3) b.y-3 - 2 (x 2) X cy -3 - 2(x-2) d. y 3 - 2 (x-2)

Sagot :

amysun2025

Answer:

[tex]y+3=2(x-2)[/tex]

Step-by-step explanation:

Pre-Solving

We are given that an equation of the line has a slope (m) of 2 and passes through the point (2, -3).
We want to write the equation of this line in point-slope form. Point-slope form is given as [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1 ,y_1)[/tex] is a point.

Solving

Substitute the values we are given into the equation.

Starting with the slope, substitute 2 for m.

[tex]y-y_1=2(x-x_1)[/tex]

Now, substitute 2 as [tex]x_1[/tex] and -3 as [tex]y_1[/tex].

[tex]y--3=2(x-2)[/tex]

This can be simplified to become:

[tex]y+3=2(x-2)[/tex]

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