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What is the temperature, in degrees Celsius, of a substance with a temperature of [tex]$49 K$[/tex]?

A. [tex]-322^{\circ} C[/tex]
B. [tex]-224^{\circ} C[/tex]
C. [tex]224^{\circ} C[/tex]
D. [tex]322^{\circ} C[/tex]


Sagot :

To convert a temperature from Kelvin (K) to degrees Celsius (°C), we use the following relationship:
[tex]\[ \text{Temperature in } °C = \text{Temperature in } K - 273.15 \][/tex]

Given the temperature in Kelvin is \( 49 \, K \), we can find the equivalent temperature in Celsius with these steps:

1. Start with the given temperature in Kelvin, which is \( 49 \, K \).
2. Subtract 273.15 from the Kelvin temperature:
[tex]\[ 49 \, K - 273.15 \][/tex]

By performing this subtraction:

[tex]\[ 49 - 273.15 = -224.15 \][/tex]

Therefore, the temperature of the substance in degrees Celsius is:

[tex]\[ -224.15^{\circ} C \][/tex]

Since we’re selecting from the closest given options, the closest and correct value is:

[tex]\[ -224^{\circ} C \][/tex]

Hence, the temperature of a substance at [tex]\( 49 \, K \)[/tex] is [tex]\(-224^{\circ} C \)[/tex].