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Find the \( y \)-intercept of the line.

[tex]\[ y = \frac{7}{10}x + \frac{11}{6} \][/tex]

[tex]\( y \)[/tex]-intercept: [tex]\(\square\)[/tex]


Sagot :

Certainly! To find the [tex]$y$[/tex]-intercept of the given line represented by the equation:

[tex]\[ y = \frac{7}{10} x + \frac{11}{6} \][/tex]

we need to determine the value of \( y \) when \( x = 0 \). The [tex]$y$[/tex]-intercept occurs at the point where the line crosses the y-axis, which is precisely when \( x = 0 \).

Here's the step-by-step process:

1. Set \( x \) to 0 in the equation:
[tex]\[ y = \frac{7}{10} \cdot 0 + \frac{11}{6} \][/tex]

2. Simplify the equation:
[tex]\[ y = 0 + \frac{11}{6} \][/tex]

3. Since \( 0 \) added to any number is the number itself, we get:
[tex]\[ y = \frac{11}{6} \][/tex]

Thus, the [tex]$y$[/tex]-intercept of the line is:

[tex]\[ \boxed{1.8333333333333333} \][/tex]

So, when rounded to a more manageable form, the [tex]$y$[/tex]-intercept is approximately 1.8333.