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A population numbers 10,000 organisms initially and decreases by [tex]$7.4 \%$[/tex] each year. Suppose [tex]$P$[/tex] represents population, and [tex]$t$[/tex] the number of years of growth. An exponential model for the population can be written in the form [tex]$P = ab^t$[/tex], where

[tex]$
P = \square
$[/tex]


Sagot :

To solve the problem of modeling a population that starts at 10,000 organisms and decreases by 7.4% each year using an exponential function, we can proceed step-by-step as follows:

1. Understand the Initial Population and the Decay Rate:
- Initial population (\(P_0\)) = 10,000 organisms
- Decay rate = 7.4%

2. Convert the Decay Rate to Decimal Form:
- Decay rate in decimal form (\(r\)) = \(-7.4\%\) = \(-\frac{7.4}{100}\) = \(-0.074\)

3. Formulate the General Exponential Model:
- The general exponential form is \(P = a b^t\), where
- \(a\) is the initial amount or population.
- \(b\) is the base of the exponential function.
- \(t\) is the time in years.

4. Define the Constants in the Model:
- \(a\) = Initial population = 10,000
- To find \(b\):
- The population decreases by 7.4% each year, meaning it retains \(100\% - 7.4\%\) of the population each year.
- Hence, \(b = 1 - 0.074 = 0.926\)

5. Consolidate the Model:
- By substituting these values into the general form, we get:
- \(P = 10000 \times 0.926^t\)

So, the exponential model for the population after \( t \) years is:
[tex]\[ P = 10000 \times 0.926^t \][/tex]

This completes the formulation of the problem.