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Ejercicio 4

Si:
[tex]\[
\begin{array}{l}
A = 30\% \text{ del } 2\% \text{ de } 5 \times 10^2 \\
B = 0.4\% \text{ del } 50\% \text{ de } 3 \times 10^3
\end{array}
\][/tex]

Hallar: el \( 0.5\% \) del \( 80\% \) de (B - A)

A) 0.012
B) 1.20
C) 0.01
D) 0.12
E) 12.1


Sagot :

Claro, resolveré el ejercicio paso a paso.

1. Calculemos el valor de \( A \):

- Primero, encontremos el \( 30\% \) del \( 2\% \) de \( 5 \times 10^2 \).
- En términos decimales, \( 30\% \) es \( 0.30 \) y \( 2\% \) es \( 0.02 \).
- Multipliquemos estos valores por el número \( 5 \times 10^2 = 500 \).

[tex]\[ A = 0.30 \times 0.02 \times 500 \][/tex]
- Calculamos:
[tex]\[ A = 0.30 \times 0.02 = 0.006 \][/tex]
[tex]\[ A = 0.006 \times 500 = 3.0 \][/tex]

Entonces, \( A = 3.0 \).

2. Calculemos el valor de \( B \):

- Primero, encontremos el \( 0.4\% \) del \( 50\% \) de \( 3 \times 10^3 \).
- En términos decimales, \( 0.4\% \) es \( 0.004 \) y \( 50\% \) es \( 0.50 \).
- Multipliquemos estos valores por el número \( 3 \times 10^3 = 3000 \).

[tex]\[ B = 0.004 \times 0.50 \times 3000 \][/tex]
- Calculamos:
[tex]\[ B = 0.004 \times 0.50 = 0.002 \][/tex]
[tex]\[ B = 0.002 \times 3000 = 6.0 \][/tex]

Entonces, \( B = 6.0 \).

3. Ahora, hallamos el \( 0.5\% \) del \( 80\% \) de \( (B - A) \):

- Primero, calculamos \( B - A \):
[tex]\[ B - A = 6.0 - 3.0 = 3.0 \][/tex]

- En términos decimales, \( 0.5\% \) es \( 0.005 \) y \( 80\% \) es \( 0.80 \).

[tex]\[ \text{Resultado} = 0.005 \times 0.80 \times 3.0 \][/tex]
- Calculamos:
[tex]\[ \text{Resultado} = 0.005 \times 0.80 = 0.004 \][/tex]
[tex]\[ \text{Resultado} = 0.004 \times 3.0 = 0.012 \][/tex]

Entonces, el \( 0.5\% \) del \( 80\% \) de \( (B - A) \) es \( 0.012 \).

La respuesta correcta es:
A) 0.012
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