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What is the molarity of a solution that was prepared by dissolving 14.2 gram of nno3 molar mass 85 in enough water make 350 ml of solution

Sagot :

Answer: 0.48M

Explanation:

Calculating Molarity:

Molarity = moles/volume (in litres)

now calculating moles of NaNO3

moles= mass/molar mass

14.2g/ 85g/mol = 0.167 moles

converting volume of solution into litres  350ml = 0.350 L

now molarity

moles/volume

0.167/0.350= 0.48M

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