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Sagot :
To determine the probability that Ethan gets a number less than 4 when he rolls a 6-sided number cube, let's go through the required steps.
1. Identify the total number of possible outcomes:
A 6-sided number cube has sides numbered 1 through 6. Therefore, there are a total of 6 possible outcomes.
2. Identify the favorable outcomes:
We need to find the probability of getting a number less than 4. The numbers less than 4 on a 6-sided cube are 1, 2, and 3. So, there are 3 favorable outcomes.
3. Calculate the probability:
Probability is given by the ratio of the number of favorable outcomes to the total number of possible outcomes. So, the probability \( P \) is calculated as:
[tex]\[ P(\text{number less than 4}) = \frac{\text{number of favorable outcomes}}{\text{total number of possible outcomes}} = \frac{3}{6} \][/tex]
4. Simplify the fraction:
Simplifying the fraction \( \frac{3}{6} \) gives:
[tex]\[ \frac{3}{6} = \frac{1}{2} \][/tex]
Hence, the probability that Ethan gets a number less than 4 is \( \frac{1}{2} \).
Therefore, the correct option is [tex]\( \boxed{\frac{1}{2}} \)[/tex], which corresponds to option [tex]\( \text{C} \)[/tex].
1. Identify the total number of possible outcomes:
A 6-sided number cube has sides numbered 1 through 6. Therefore, there are a total of 6 possible outcomes.
2. Identify the favorable outcomes:
We need to find the probability of getting a number less than 4. The numbers less than 4 on a 6-sided cube are 1, 2, and 3. So, there are 3 favorable outcomes.
3. Calculate the probability:
Probability is given by the ratio of the number of favorable outcomes to the total number of possible outcomes. So, the probability \( P \) is calculated as:
[tex]\[ P(\text{number less than 4}) = \frac{\text{number of favorable outcomes}}{\text{total number of possible outcomes}} = \frac{3}{6} \][/tex]
4. Simplify the fraction:
Simplifying the fraction \( \frac{3}{6} \) gives:
[tex]\[ \frac{3}{6} = \frac{1}{2} \][/tex]
Hence, the probability that Ethan gets a number less than 4 is \( \frac{1}{2} \).
Therefore, the correct option is [tex]\( \boxed{\frac{1}{2}} \)[/tex], which corresponds to option [tex]\( \text{C} \)[/tex].
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