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Question 5 of 10

\begin{tabular}{|c|c|c|}
\hline Place & Is a city & Is in North America \\
\hline India & & \\
\hline Tokyo & [tex]$\checkmark$[/tex] & \\
\hline Houston & [tex]$\checkmark$[/tex] & [tex]$\checkmark$[/tex] \\
\hline Peru & & \\
\hline New York & [tex]$\checkmark$[/tex] & [tex]$\checkmark$[/tex] \\
\hline Tijuana & [tex]$\checkmark$[/tex] & [tex]$\checkmark$[/tex] \\
\hline Canada & & [tex]$\checkmark$[/tex] \\
\hline
\end{tabular}

Let event [tex]$A=$[/tex] The place is a city.
Let event [tex]$B=$[/tex] The place is in North America.

Which outcomes are in [tex]$A$[/tex] or [tex]$B$[/tex]?

Sagot :

GinnyAnswer
To determine the outcomes in event \( A \) or \( B \), we need to identify the elements in either event \( A \) or event \( B \).

Firstly, let's list the elements in each event based on the provided table:
- Event \( A \): The place is a city.
- Tokyo
- Houston
- New York
- Tijuana

- Event \( B \): The place is in North America.
- Houston
- New York
- Tijuana
- Canada

Next, we need to find the union of these two sets, which includes all the elements that are in either set \( A \) or set \( B \). This means we combine the elements of both sets, ensuring that we list each unique element only once.

The elements in set \( A \) are:
- Tokyo
- Houston
- New York
- Tijuana

The elements in set \( B \) are:
- Houston
- New York
- Tijuana
- Canada

Taking the union of these sets (combining all unique elements), we get:
- Tokyo
- Houston
- New York
- Tijuana
- Canada

Therefore, the outcomes in \( A \) or \( B \) are:
[tex]\[ \{ \text{Tokyo}, \text{Houston}, \text{New York}, \text{Tijuana}, \text{Canada} \} \][/tex]
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