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Paul is gathering data about moss growth in a local forest. He measured an area of 11 square centimeters on one particular tree and will come back in 6 months to measure the growth of the moss. If the area covered by moss multiplies by one and a half times each month, approximately how much area will the moss cover when Paul returns?

A. [tex]$14.7 \, cm^2$[/tex]
B. [tex]$16.5 \, cm^2$[/tex]
C. [tex]$125.3 \, cm^2$[/tex]
D. [tex]$99.1 \, cm^2$[/tex]


Sagot :

To solve this problem, let’s start by understanding how exponential growth works. The area covered by moss increases each month by multiplying by a growth rate. In this scenario, the initial area of the moss is 11 square centimeters, and the growth rate is 1.5 times per month over a span of 6 months.

The formula to find the final area after exponential growth is given by:
[tex]\[ \text{Final Area} = \text{Initial Area} \times (\text{Growth Rate})^{\text{Number of Months}} \][/tex]

Plugging in the given values:
[tex]\[ \text{Initial Area} = 11 \, \text{cm}^2 \][/tex]
[tex]\[ \text{Growth Rate} = 1.5 \][/tex]
[tex]\[ \text{Number of Months} = 6 \][/tex]

So, the calculation is:
[tex]\[ \text{Final Area} = 11 \times (1.5)^6 \][/tex]

Following through with the calculation:
1. Calculate \( 1.5^6 \)
2. Multiply the result by 11

After performing the necessary calculations, we arrive at the final area as approximately \( 125.3 \, \text{cm}^2 \).

Thus, the correct answer is:
[tex]\[ \boxed{125.3 \, \text{cm}^2} \][/tex]
which corresponds to option:
C. [tex]\(125.3 \, \text{cm}^2\)[/tex]