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The elements that compose seawater, along with the corresponding percentages, are shown in the table below.

If a sample of seawater contains [tex]$60 \, ml[tex]$[/tex], how many [tex]$[/tex]ml$[/tex] of oxygen are in the sample?

\begin{tabular}{|lr|}
\hline
& Seawater Elements \\
\hline
Chemical & Percent \\
\hline
Oxygen & [tex]$85.84 \%$[/tex] \\
\hline
Hydrogen & [tex]$10.82 \%$[/tex] \\
\hline
Chlorine & [tex]$1.94 \%$[/tex] \\
\hline
Sodium & [tex]$1.08 \%$[/tex] \\
\hline
Magnesium & [tex]$0.13 \%$[/tex] \\
\hline
Other elements & [tex]$0.19 \%$[/tex] \\
\hline
\end{tabular}

There are [tex]\square \, ml[/tex] of oxygen in the sample.
(Type an integer or a decimal rounded to two decimal places.)


Sagot :

To solve the problem of how many milliliters of oxygen are in a 60 ml sample of seawater, given that the oxygen percentage is 85.84%, follow these steps:

1. Identify the given data:
- The total volume of the seawater sample: \( 60 \) ml
- The percentage of oxygen in the sample: \( 85.84 \% \)

2. Convert the percentage of oxygen to a decimal for calculation:
- \( 85.84\% = 0.8584 \)

3. Multiply the total volume of the sample by the decimal form of the oxygen percentage to find the oxygen volume in the sample:
- \( \text{Volume of oxygen} = \text{Total volume} \times \text{Oxygen percent as a decimal} \)
- \( \text{Volume of oxygen} = 60 \, \text{ml} \times 0.8584 \)

4. Calculate the resulting volume:
- \( \text{Volume of oxygen} = 60 \times 0.8584 = 51.504 \, \text{ml} \)

Thus, there are [tex]\( 51.504 \)[/tex] ml of oxygen in the 60 ml sample of seawater.
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