Let's solve the problem step by step.
1. Identify the theoretical probability:
- For a fair coin, the probability of getting heads (H) is always \(0.5\). This is the theoretical probability.
2. Count the number of heads (H) observed in the 10 flips:
- From the table, let's count the occurrences of heads.
[tex]\[
\begin{array}{|c|c|c|c|c|c|c|c|c|c|c|}
\hline
Flip & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 \\
\hline
Result & T & T & T & H & T & T & T & H & T & T \\
\hline
\end{array}
\][/tex]
- Heads appear in the 4th and 8th flips, so we observed heads 2 times.
3. Determine the total number of flips:
- The coin was flipped 10 times in total.
4. Calculate the empirical probability of getting heads:
- The empirical probability is given by the ratio of the number of heads observed to the total number of flips.
[tex]\[
\text{Empirical Probability} = \frac{\text{Number of Heads}}{\text{Total Number of Flips}} = \frac{2}{10} = 0.2
\][/tex]
5. Find the difference between the theoretical and empirical probabilities:
- Theoretical Probability of Heads = \(0.5\)
- Empirical Probability of Heads = \(0.2\)
- The difference between the theoretical and empirical probabilities is:
[tex]\[
\text{Difference} = |0.5 - 0.2| = 0.3
\][/tex]
So, the correct answer is:
[tex]\[ \boxed{0.3} \][/tex]
Therefore, the answer is option B: 0.3.
