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(b) Find h^-1(x)
h(x) = 8 x² +12x​


Sagot :

Answer:

The given function is,

f

(x)=x2+2x+1x2−8x+12

⇒f(x)=x2+2x+1

(x−6) (x−2)

It can be seen that function

f

is defined for all real numbers except at

x=6 and x=2

Hence the domain of

f

is

R−{2,6}

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