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Sagot :
To determine the Maximum Material Condition (MMC) for the given pipe, we need to find the largest possible diameter for the outside diameter (OD) and the smallest possible diameter for the inside diameter (ID).
### Step-by-Step Solution:
1. Outside Diameter (OD) Analysis:
- The nominal (average) outside diameter (OD) of the pipe is given as \( 3.50 \) inches.
- The tolerance for the outside diameter is \( \pm 0.02 \) inches. This means the OD can vary from \( 3.50 - 0.02 = 3.48 \) inches (minimum) to \( 3.50 + 0.02 = 3.52 \) inches (maximum).
[tex]\[ \text{OD minimum} = 3.50 - 0.02 = 3.48 \text{ inches} \][/tex]
[tex]\[ \text{OD maximum} = 3.50 + 0.02 = 3.52 \text{ inches} \][/tex]
For the Maximum Material Condition (MMC) of the OD, we consider the largest possible diameter, which is \( 3.52 \) inches.
2. Inside Diameter (ID) Analysis:
- The nominal (average) inside diameter (ID) of the pipe is given as \( 2.50 \) inches.
- The tolerance for the inside diameter is \( \pm 0.05 \) inches. This means the ID can vary from \( 2.50 - 0.05 = 2.45 \) inches (minimum) to \( 2.50 + 0.05 = 2.55 \) inches (maximum).
[tex]\[ \text{ID minimum} = 2.50 - 0.05 = 2.45 \text{ inches} \][/tex]
[tex]\[ \text{ID maximum} = 2.50 + 0.05 = 2.55 \text{ inches} \][/tex]
For the Maximum Material Condition (MMC) of the ID, we consider the smallest possible diameter, which is \( 2.45 \) inches.
### Conclusion:
- The Maximum Material Condition (MMC) for the outside diameter (OD) of the pipe is \( 3.52 \) inches.
- The Maximum Material Condition (MMC) for the inside diameter (ID) of the pipe is \( 2.45 \) inches.
Thus, the answers are:
- OD at MMC: \( 3.52 \)
- ID at MMC: [tex]\( 2.45 \)[/tex]
### Step-by-Step Solution:
1. Outside Diameter (OD) Analysis:
- The nominal (average) outside diameter (OD) of the pipe is given as \( 3.50 \) inches.
- The tolerance for the outside diameter is \( \pm 0.02 \) inches. This means the OD can vary from \( 3.50 - 0.02 = 3.48 \) inches (minimum) to \( 3.50 + 0.02 = 3.52 \) inches (maximum).
[tex]\[ \text{OD minimum} = 3.50 - 0.02 = 3.48 \text{ inches} \][/tex]
[tex]\[ \text{OD maximum} = 3.50 + 0.02 = 3.52 \text{ inches} \][/tex]
For the Maximum Material Condition (MMC) of the OD, we consider the largest possible diameter, which is \( 3.52 \) inches.
2. Inside Diameter (ID) Analysis:
- The nominal (average) inside diameter (ID) of the pipe is given as \( 2.50 \) inches.
- The tolerance for the inside diameter is \( \pm 0.05 \) inches. This means the ID can vary from \( 2.50 - 0.05 = 2.45 \) inches (minimum) to \( 2.50 + 0.05 = 2.55 \) inches (maximum).
[tex]\[ \text{ID minimum} = 2.50 - 0.05 = 2.45 \text{ inches} \][/tex]
[tex]\[ \text{ID maximum} = 2.50 + 0.05 = 2.55 \text{ inches} \][/tex]
For the Maximum Material Condition (MMC) of the ID, we consider the smallest possible diameter, which is \( 2.45 \) inches.
### Conclusion:
- The Maximum Material Condition (MMC) for the outside diameter (OD) of the pipe is \( 3.52 \) inches.
- The Maximum Material Condition (MMC) for the inside diameter (ID) of the pipe is \( 2.45 \) inches.
Thus, the answers are:
- OD at MMC: \( 3.52 \)
- ID at MMC: [tex]\( 2.45 \)[/tex]
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