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1. What are the extremes of the following proportion?

[tex]\[ \frac{3}{15} = \frac{12}{60} \][/tex]

A. 3 and 15
B. 12 and 60
C. 3 and 60
D. 15 and 12


Sagot :

To determine the extremes of the proportion \( \frac{3}{15} = \frac{12}{60} \), we need to identify the first and last terms of the proportion. In any given proportion of the form \( \frac{a}{b} = \frac{c}{d} \), the extremes are the terms \( a \) and \( d \).

Let's break down the given proportion step by step:
1. The given proportion is:
[tex]\[ \frac{3}{15} = \frac{12}{60} \][/tex]

2. In the proportion \( \frac{3}{15} = \frac{12}{60} \), the first term is the numerator of the first fraction, which is \( 3 \).

3. The last term is the denominator of the second fraction, which is \( 60 \).

Therefore, the extremes of the proportion \( \frac{3}{15} = \frac{12}{60} \) are 3 and 60.

So, the correct answer is:

C. 3 and 60