Answered

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Solve for \( b \):

[tex]\[ 4 - 2(b - 6) = 12 \][/tex]

A. \( b = 2 \)

B. \( b = 12 \)

C. \( b = -2 \)

D. [tex]\( b = -10 \)[/tex]

Sagot :

GinnyAnswer
Sure, let's solve the equation step-by-step. We're given the equation:

[tex]\[ 4 - 2(b - 6) = 12 \][/tex]

First, let's simplify the expression inside the parentheses and distribute the \(-2\):

[tex]\[ 4 - 2(b - 6) = 4 - 2b + 12 \][/tex]

Next, let's combine like terms on the left side:

[tex]\[ 4 + 12 - 2b = 16 - 2b \][/tex]

So, the equation becomes:

[tex]\[ 16 - 2b = 12 \][/tex]

Now, let's isolate the term with the variable by subtracting 16 from both sides:

[tex]\[ 16 - 2b - 16 = 12 - 16 \][/tex]

This simplifies to:

[tex]\[ -2b = -4 \][/tex]

Now, divide both sides by \(-2\) to solve for \(b\):

[tex]\[ b = \frac{-4}{-2} = 2 \][/tex]

So, the correct solution is [tex]\(\boxed{2}\)[/tex].
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