Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

Find the inverse of the function.

[tex]\[ y = 2x^2 - 4 \][/tex]

A. \( y = \pm \sqrt{x} + 2 \)
B. \( y = \pm \sqrt{\frac{x + 4}{2}} \)
C. \( y = \pm \frac{\sqrt{x + 4}}{2} \)
D. [tex]\( y = \pm \sqrt{x} - 2 \)[/tex]


Sagot :

To find the inverse of the function \( y = 2x^2 - 4 \), follow these steps:

1. Start with the given function:
[tex]\[ y = 2x^2 - 4 \][/tex]

2. Swap \(y\) and \(x\): To find the inverse, we interchange the roles of \(x\) and \(y\).
[tex]\[ x = 2y^2 - 4 \][/tex]

3. Solve for \(y\): We need to isolate \(y\) in terms of \(x\).

- First, add 4 to both sides to start isolating \(y^2\):
[tex]\[ x + 4 = 2y^2 \][/tex]

- Next, divide both sides by 2 to further isolate \(y^2\):
[tex]\[ \frac{x + 4}{2} = y^2 \][/tex]

- Finally, take the square root of both sides to solve for \(y\):
[tex]\[ y = \pm \sqrt{\frac{x + 4}{2}} \][/tex]

4. State the inverse functions:
The resulting expressions represent the inverse functions of the given original function. Therefore, we have:
[tex]\[ y = \pm \sqrt{\frac{x + 4}{2}} \][/tex]
And equivalently, since taking the square root of a fraction is the same as taking the square root of the numerator and denominator separately:
[tex]\[ y = \pm \frac{\sqrt{x + 4}}{2} \][/tex]

Thus, the inverse functions of the original function \( y = 2x^2 - 4 \) are:
[tex]\[ y = \pm \sqrt{\frac{x + 4}{2}} \][/tex]
or equivalently:
[tex]\[ y = \pm \frac{\sqrt{x + 4}}{2} \][/tex]

So, the correct answer is:
[tex]\[ y = \pm \sqrt{\frac{x+4}{2}} \][/tex]
or
[tex]\[ y = \pm \frac{\sqrt{x+4}}{2} \][/tex]