Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Join our platform to connect with experts ready to provide precise answers to your questions in various areas. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
Certainly! Let's determine the values of \(a\) and \(b\) for the exponential function \(f(x) = a \cdot b^x\) given that it passes through the points \((0, 11)\) and \((3, 88)\).
### Step 1: Determine \(a\)
First, we use the point \((0, 11)\).
When \(x = 0\):
[tex]\[ f(0) = a \cdot b^0 \][/tex]
Since \(b^0 = 1\):
[tex]\[ f(0) = a \cdot 1 = a \][/tex]
Given that \(f(0) = 11\):
[tex]\[ a = 11 \][/tex]
So, we have:
[tex]\[ a = 11 \][/tex]
### Step 2: Determine \(b\)
Now, using the second point \((3, 88)\).
When \(x = 3\):
[tex]\[ f(3) = a \cdot b^3 \][/tex]
We already found that \(a = 11\), so:
[tex]\[ 88 = 11 \cdot b^3 \][/tex]
To solve for \(b\), divide both sides by 11:
[tex]\[ \frac{88}{11} = b^3 \][/tex]
[tex]\[ 8 = b^3 \][/tex]
Now, take the cube root of both sides to find \(b\):
[tex]\[ b = \sqrt[3]{8} \][/tex]
[tex]\[ b = 2 \][/tex]
### Final values:
[tex]\[ \begin{array}{l} a = 11 \\ b = 2 \end{array} \][/tex]
Thus, the values are:
[tex]\[ a = 11 \][/tex]
[tex]\[ b = 2 \][/tex]
### Step 1: Determine \(a\)
First, we use the point \((0, 11)\).
When \(x = 0\):
[tex]\[ f(0) = a \cdot b^0 \][/tex]
Since \(b^0 = 1\):
[tex]\[ f(0) = a \cdot 1 = a \][/tex]
Given that \(f(0) = 11\):
[tex]\[ a = 11 \][/tex]
So, we have:
[tex]\[ a = 11 \][/tex]
### Step 2: Determine \(b\)
Now, using the second point \((3, 88)\).
When \(x = 3\):
[tex]\[ f(3) = a \cdot b^3 \][/tex]
We already found that \(a = 11\), so:
[tex]\[ 88 = 11 \cdot b^3 \][/tex]
To solve for \(b\), divide both sides by 11:
[tex]\[ \frac{88}{11} = b^3 \][/tex]
[tex]\[ 8 = b^3 \][/tex]
Now, take the cube root of both sides to find \(b\):
[tex]\[ b = \sqrt[3]{8} \][/tex]
[tex]\[ b = 2 \][/tex]
### Final values:
[tex]\[ \begin{array}{l} a = 11 \\ b = 2 \end{array} \][/tex]
Thus, the values are:
[tex]\[ a = 11 \][/tex]
[tex]\[ b = 2 \][/tex]
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.