To determine the output of the given program, let's analyze it step by step:
1. The set [tex]$d$[/tex] is initialized with the elements [tex]$\{0, 1, 2\}$[/tex].
2. The program uses a for loop to iterate over each element in the set [tex]$d$[/tex].
3. Within the loop, the program prints each element [tex]$x$[/tex].
The elements of the set [tex]$d = \{0, 1, 2\}$[/tex] are [tex]$0$[/tex], [tex]$1$[/tex], and [tex]$2$[/tex]. As the loop iterates through the set, it prints each of these elements on separate lines in sequence.
Here’s a detailed breakdown of each iteration:
- In the first iteration, [tex]$x = 0$[/tex], so [tex]$\operatorname{print}(0)$[/tex] will print [tex]$0$[/tex].
- In the second iteration, [tex]$x = 1$[/tex], so [tex]$\operatorname{print}(1)$[/tex] will print [tex]$1$[/tex].
- In the third iteration, [tex]$x = 2$[/tex], so [tex]$\operatorname{print}(2)$[/tex] will print [tex]$2$[/tex].
Therefore, the output of this program is a sequence of the elements [tex]$0$[/tex], [tex]$1$[/tex], and [tex]$2$[/tex] printed on the same line, concatenated together, producing the sequence "012".
So, the correct answer is:
b. 012
