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Sumy is working in geometry class and is given figure [tex]$ABCD$[/tex] in the coordinate plane to reflect. The coordinates of point [tex]$D$[/tex] are [tex]$(a, b)$[/tex] and she reflects the figure over the line [tex]$y=x$[/tex]. What are the coordinates of the image [tex]$D^{\prime}$[/tex]?

A. [tex]$(a, -b)$[/tex]
B. [tex]$(b, a)$[/tex]
C. [tex]$(-a, b)$[/tex]
D. [tex]$(-b, -a)$[/tex]


Sagot :

To solve the problem of finding the coordinates of the reflected point \( D^{\prime} \) when reflecting point \( D(a, b) \) over the line \( y = x \), let's follow these steps:

1. Understanding the Reflection over \( y = x \):
When reflecting a point over the line \( y = x \), the coordinates of the point are swapped. This means that if \( D \) has coordinates \( (a, b) \), the coordinates of its reflection over the line \( y = x \) will be \( (b, a) \).

2. Reflection Process:
- The original point \( D \) is given as \( (a, b) \).
- The reflection of point \( (a, b) \) over the line \( y = x \) involves swapping the \( x \) and \( y \) coordinates.

3. Finding the Coordinates of \( D^{\prime} \):
- After swapping the coordinates of point \( D(a, b) \), the new coordinates will be \( (b, a) \).

Therefore, the coordinates of the image \( D^{\prime} \) after reflecting point \( D \) over the line \( y = x \) are \( (b, a) \).

So, the answer is:
[tex]\[ \boxed{(b, a)} \][/tex]
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