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Solve for \( x \).

[tex]\[ 3x = 6x - 2 \][/tex]

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2) [tex]\[ \frac{30}{2c} = \frac{20}{12} \][/tex]

Sagot :

Let's solve the equation step-by-step:

[tex]\[ \frac{30}{2c} = \frac{20}{12} \][/tex]

1. Simplify the right side of the equation:

[tex]\[ \frac{20}{12} = \frac{20 \div 4}{12 \div 4} = \frac{5}{3} \][/tex]

So the equation now looks like this:

[tex]\[ \frac{30}{2c} = \frac{5}{3} \][/tex]

2. To eliminate the fractions, we can cross-multiply. Cross-multiplication will give us:

[tex]\[ 30 \times 3 = 5 \times (2c) \][/tex]

Simplify both sides:

[tex]\[ 90 = 10c \][/tex]

3. Solve for \( c \):

[tex]\[ c = \frac{90}{10} \][/tex]

[tex]\[ c = 9 \][/tex]

So the solution to the equation \(\frac{30}{2c} = \frac{20}{12}\) is \( c = 9 \).

To ensure our solution is correct, we can substitute \( c \) back into the original equation and check:

[tex]\[ \frac{30}{2 \times 9} = \frac{30}{18} = \frac{5}{3} = \frac{20}{12} \][/tex]

This confirms the solution \( c = 9 \) is correct.

Additionally, the simplified right side of the equation was \(\frac{5}{3} \approx 1.6667\). Therefore, the solution yields:
\(
\left(1.6667, 9\right)
\).