Answered

Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Explore our Q&A platform to find reliable answers from a wide range of experts in different fields. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

Consider the following intermediate chemical equations:
[tex]\[
\begin{array}{l}
2 P (s) + 3 Cl_2 (g) \rightarrow 2 PCl_3 (l) \\
PCl_3 (l) + Cl_2 (g) \rightarrow PCl_5 (s)
\end{array}
\][/tex]

When you combine the intermediate chemical equations, which substance do you cancel out?

A. \( P \)

B. \( Cl_2 \)

C. \( PCl_3 \)

D. [tex]\( PCl \)[/tex]

Sagot :

GinnyAnswer
To find out which substance cancels out when combining the two given intermediate chemical equations, we should follow the steps below:

1. Identify the given equations:

[tex]\[ 2 P (s) + 3 Cl_2 (g) \rightarrow 2 PCl_3 (l) \][/tex]

[tex]\[ PCl_3 (l) + Cl_2 (g) \rightarrow PCl_5 (s) \][/tex]

2. Observe which substances appear in both equations:

- The first equation produces \(2 PCl_3 (l)\).
- The second equation consumes \(PCl_3 (l)\).

3. Combine the two equations:

To combine them, we add the reactions and cancel out any substance that appears on both the reactant and product sides:

[tex]\[ 2 P (s) + 3 Cl_2 (g) \rightarrow 2 PCl_3 (l) \][/tex]

[tex]\[ PCl_3 (l) + Cl_2 (g) \rightarrow PCl_5 (s) \][/tex]

4. Cancel out the common substance:

Since \(PCl_3 (l)\) appears as a product in the first equation and as a reactant in the second equation, it will cancel out when we combine the equations:

[tex]\[ (2 P (s) + 3 Cl_2 (g) \rightarrow 2 PCl_3 (l)) + (PCl_3 (l) + Cl_2 (g) \rightarrow PCl_5 (s)) \][/tex]

Simplifies to:

[tex]\[ 2 P (s) + 3 Cl_2 (g) + PCl_3 (l) + Cl_2 (g) \rightarrow 2 PCl_3 (l) + PCl_5 (s) \][/tex]

After canceling the \(2 PCl_3 (l)\) that appears on both sides:

[tex]\[ 2 P (s) + 4 Cl_2 (g) \rightarrow PCl_5 (s) \][/tex]

Thus, the substance that cancels out when combining the equations is \(PCl_3\).

Therefore, the correct answer is [tex]\(PCl_3\)[/tex].
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.