To determine how many megabytes Agent Hunt transfers every 10 seconds, we can analyze the function modeling the transfer.
Given:
[tex]\[ S = 5t + 45 \][/tex]
This equation models the size of the files on the flash drive after \( t \) seconds.
Now, let’s break down the equation. The term \( 5t \) represents the amount of data transferred after \( t \) seconds, since it is directly proportional to \( t \). The constant 45 represents the amount of data already on the flash drive before the transfer begins.
We need to calculate the amount of data transferred specifically over a time period of 10 seconds. The coefficient of \( t \) in the equation \( 5t \) tells us that data is being transferred at a rate of 5 megabytes per second. To find out how much data is transferred in 10 seconds, we use the rate of transfer:
[tex]\[ \text{Data transferred in 10 seconds} = 5 \, \text{megabytes/second} \times 10 \, \text{seconds} \][/tex]
Multiplying the rate by the duration:
[tex]\[ 5 \times 10 = 50 \][/tex]
So, Agent Hunt transfers [tex]\(\boxed{50}\)[/tex] megabytes every 10 seconds.
