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Simplify the following:

[tex]
\begin{array}{l}
7^1 = \\
4^0 = \\
6^{-1} =
\end{array}
\]

Sagot :

Certainly! Let's simplify these expressions step-by-step.

### Step 1: Simplifying \(7^1\)
When any number is raised to the power of 1, the result is the number itself. Therefore:
[tex]\[ 7^1 = 7 \][/tex]

### Step 2: Simplifying \(4^0\)
Any number raised to the power of 0 is equal to 1, provided the base is not zero. Therefore:
[tex]\[ 4^0 = 1 \][/tex]

### Step 3: Simplifying \(6^{-1}\)
When a number is raised to a negative exponent, it is equivalent to taking the reciprocal of the number raised to the positive of that exponent. Therefore:
[tex]\[ 6^{-1} = \frac{1}{6} \approx 0.16666666666666666 \][/tex]

So, the simplified results for the given expressions are:
[tex]\[ 7^1 = 7 \][/tex]
[tex]\[ 4^0 = 1 \][/tex]
[tex]\[ 6^{-1} = 0.16666666666666666 \][/tex]

Therefore, the simplified forms of the expressions are:
[tex]\[ 7, 1, \text{ and } 0.16666666666666666 \][/tex]