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Match each expression on the left with its quotient on the right.

[tex]\[
\begin{array}{l}
1. \ (x^2 - x - 30) \div (x - 6) \\
2. \ (x^3 - 2x^2 - 7x - 4) \div (x^2 + 2x + 1) \\
3. \ (x^3 + 2x^2 - 1) \div (x^2 - x + 1)
\end{array}
\][/tex]

[tex]\[
\begin{array}{l}
A. \ x + 3 \ \text{R} \ 2x - 4 \\
B. \ x + 5 \\
C. \ x - 4
\end{array}
\][/tex]


Sagot :

Let's match each given expression with its quotient and remainder when divided by its corresponding divisor. We'll analyze each pair of expressions and divisors step-by-step.

1. For the first expression:
[tex]\[ \frac{x^2 - x - 30}{x - 6} \][/tex]
The quotient and remainder for this division are:
[tex]\[ x + 5 \quad (R = 0) \][/tex]

So, the result for this division is \(x + 5\) with a remainder of 0.

2. For the second expression:
[tex]\[ \frac{x^3 - 2x^2 - 7x - 4}{x^2 + 2x + 1} \][/tex]
The quotient and remainder for this division are:
[tex]\[ x - 4 \quad (R = 0) \][/tex]

So, the result for this division is \(x - 4\) with a remainder of 0.

3. For the third expression:
[tex]\[ \frac{x^3 + 2x^2 - 1}{x^2 - x + 1} \][/tex]
The quotient and remainder for this division are:
[tex]\[ x + 3 \quad (R = 2x - 4) \][/tex]

So, the result for this division is \(x + 3\) with a remainder of \(2x - 4\).

Now, let's match the expressions with their corresponding quotients and remainders:

- \(\frac{x^2 - x - 30}{x - 6}\) matches with \(x + 5 \text{ with remainder } 0\).
- \(\frac{x^3 - 2x^2 - 7x - 4}{x^2 + 2x + 1}\) matches with \(x - 4 \text{ with remainder } 0\).
- \(\frac{x^3 + 2x^2 - 1}{x^2 - x + 1}\) matches with \(x + 3 \text{ with remainder } 2x - 4\).

Therefore, the correct matches are:
[tex]\[ \begin{array}{l} \left(x^2-x-30\right) \div(x-6) \quad \rightarrow \quad x+5 \\ \left(x^3-2 x^2-7 x-4\right) \div\left(x^2+2 x+1\right) \quad \rightarrow \quad x-4 \\ \left(x^3+2 x^2-1\right) \div\left(x^2-x+1\right) \quad \rightarrow \quad x+3 \text{ with remainder } 2x-4 \\ \end{array} \][/tex]