Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Ask your questions and receive detailed answers from professionals with extensive experience in various fields. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
To find the distance \( d \) between two points \( C \) and \( D \) with coordinates \( (-1, 4) \) and \( (2, 0) \) respectively, we will use the distance formula:
[tex]\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]
Let’s go through the steps to find this distance:
1. Identify coordinates:
- \( x_1 = -1 \)
- \( y_1 = 4 \)
- \( x_2 = 2 \)
- \( y_2 = 0 \)
2. Calculate the differences:
- Difference in the x-coordinates (\( \Delta x \)):
[tex]\[ \Delta x = x_2 - x_1 = 2 - (-1) = 2 + 1 = 3 \][/tex]
- Difference in the y-coordinates (\( \Delta y \)):
[tex]\[ \Delta y = y_2 - y_1 = 0 - 4 = -4 \][/tex]
3. Square the differences:
- Square of \( \Delta x \):
[tex]\[ (\Delta x)^2 = 3^2 = 9 \][/tex]
- Square of \( \Delta y \):
[tex]\[ (\Delta y)^2 = (-4)^2 = 16 \][/tex]
4. Sum of the squared differences:
[tex]\[ (\Delta x)^2 + (\Delta y)^2 = 9 + 16 = 25 \][/tex]
5. Calculate the distance:
[tex]\[ d = \sqrt{(\Delta x)^2 + (\Delta y)^2} = \sqrt{25} = 5 \][/tex]
Therefore, the distance between points \( C(-1, 4) \) and \( D(2, 0) \) is
[tex]\[ \boxed{5} \text{ units}. \][/tex]
[tex]\[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \][/tex]
Let’s go through the steps to find this distance:
1. Identify coordinates:
- \( x_1 = -1 \)
- \( y_1 = 4 \)
- \( x_2 = 2 \)
- \( y_2 = 0 \)
2. Calculate the differences:
- Difference in the x-coordinates (\( \Delta x \)):
[tex]\[ \Delta x = x_2 - x_1 = 2 - (-1) = 2 + 1 = 3 \][/tex]
- Difference in the y-coordinates (\( \Delta y \)):
[tex]\[ \Delta y = y_2 - y_1 = 0 - 4 = -4 \][/tex]
3. Square the differences:
- Square of \( \Delta x \):
[tex]\[ (\Delta x)^2 = 3^2 = 9 \][/tex]
- Square of \( \Delta y \):
[tex]\[ (\Delta y)^2 = (-4)^2 = 16 \][/tex]
4. Sum of the squared differences:
[tex]\[ (\Delta x)^2 + (\Delta y)^2 = 9 + 16 = 25 \][/tex]
5. Calculate the distance:
[tex]\[ d = \sqrt{(\Delta x)^2 + (\Delta y)^2} = \sqrt{25} = 5 \][/tex]
Therefore, the distance between points \( C(-1, 4) \) and \( D(2, 0) \) is
[tex]\[ \boxed{5} \text{ units}. \][/tex]
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.