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Gold has a density of 20 g over cubic centimeters what is the mass in kilograms of a cubic goals measuring 3 inches on each side?

Sagot :

Heather

Answer:  8.84901456 kg or about 8.85 kg

Explanation:

       Mass can be calculated with the following formula, where ρ is the density and v is the volume:

               Mass = ρ * v

       We will substitute our known values and solve. Remember that the volume of a cube is x³ when x is the side length.

       Keep in mind that 1 inch is equal to 2.54 centimeters.

               Mass = ρ * v

               Mass = (20 g/cm³) * (7.62 cm)³

               Mass = (20 g/cm³) * (442.450728 cm³)

               Mass = 8,849.01456 g

       Next, there are 1,000 grams in a kilogram.

               8,849.01456 g / 1,000 = 8.84901456 kg

       We can also round to the nearest hundredth, if necessary.

               8.84901456 kg ≈ 8.85 kg
The volume of the cube is (7 inches * 7 inches * 7 inches) / (1728 inches³ / ft³) = 0.125 ft³. The mass of the gold is 0.125 ft³ * 20 g/cm³ * (100 cm / 1 ft)³ = 125 kg.
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