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Write an equation for the cubic polynomial function whose graph has zeroes at 2, 3, and 5.

Can any of the roots have multiplicity?
How can you find a function that has these

Sagot :

jsstory001

Answer:

Step-by-step explanation:

To write the equation for a cubic polynomial function whose graph has zeroes at 2, 3, and 5, we start by using the fact that these roots imply the polynomial can be written in the form:

P(x) = a(x - 2)(x - 3)(x - 5)

Here, a is a non-zero constant that can be any real number. If we assume a = 1 for simplicity, the polynomial becomes:

P(x) = (x - 2)(x - 3)(x - 5)

Now, let’s expand this polynomial:

First, expand \(x - 2)(x - 3):

(x - 2)(x - 3) = x^2 - 3x - 2x + 6 = x^2 - 5x + 6

Next, multiply this result by (x - 5):

(x^2 - 5x + 6)(x - 5)

= x^3 - 5x^2 + 6x - 5x^2 + 25x - 30

= x^3 - 10x^2 + 31x - 30

Thus, the cubic polynomial with zeroes at 2, 3, and 5 is:

P(x) = x^3 - 10x^2 + 31x - 30

Regarding multiplicity, none of the roots 2, 3, or 5 have a multiplicity greater than 1 in the current polynomial because each factor (x - 2), (x - 3), and (x - 5) appears exactly once.

If any root were to have a multiplicity greater than 1, the polynomial would no longer be cubic; instead, it would have a higher degree. For example, if the root (2) had a multiplicity of 2, the polynomial would be:

P(x) = a(x - 2)^2(x - 3)(x - 5)

This polynomial is quartic (degree 4), not cubic.

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