Answered

Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Get immediate and reliable answers to your questions from a community of experienced professionals on our platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

QUESTION 4
A certain acid has a pH of 4.5. What would be the complementary pOH value?

QUESTION 5
What is the pH of a 0.0235 M HCl solution?

QUESTION 6
What is the pH of a [tex]6.50 \times 10^{-5}[/tex] M KOH solution?

Sagot :

GinnyAnswer
Sure, let's solve each question step-by-step.

---

Question 4:

A certain acid has a pH of 4.5. What would be the complimentary pOH value?

Solution:
1. The relationship between pH and pOH can be expressed using the formula:
[tex]\[ \text{pH} + \text{pOH} = 14 \][/tex]
2. Given the pH of the acid is 4.5, we can substitute this value into the equation:
[tex]\[ 4.5 + \text{pOH} = 14 \][/tex]
3. Solving for pOH:
[tex]\[ \text{pOH} = 14 - 4.5 = 9.5 \][/tex]

So, the complimentary pOH value is 9.5.

---

Question 5:

What is the pH of 0.0235M HCl solution?

Solution:
1. Hydrochloric acid (HCl) is a strong acid, which means it completely dissociates in water. Thus, the concentration of H\(^+\) ions is equal to the concentration of the HCl solution, which is 0.0235M.
2. The pH is calculated using the formula:
[tex]\[ \text{pH} = -\log_{10}[\text{H}^+] \][/tex]
3. Substituting the given concentration:
[tex]\[ \text{pH} = -\log_{10}(0.0235) \][/tex]
4. The calculated pH value is approximately:
[tex]\[ \text{pH} \approx 1.6289321377282637 \][/tex]

So, the pH of the 0.0235M HCl solution is approximately 1.6289.

---

Question 6:

What is the pH of a 6.50 x 10^-6 M KOH solution?

Solution:
1. Potassium hydroxide (KOH) is a strong base, which means it completely dissociates in water. Thus, the concentration of OH\(^-\) ions is equal to the concentration of the KOH solution, which is 6.50 x 10^-6 M.
2. The pOH is calculated using the formula:
[tex]\[ \text{pOH} = -\log_{10}[\text{OH}^-] \][/tex]
3. Substituting the given concentration:
[tex]\[ \text{pOH} = -\log_{10}(6.50 \times 10^{-6}) \][/tex]
4. The calculated pOH value is approximately:
[tex]\[ \text{pOH} \approx 5.187086643357144 \][/tex]
5. The pH can be found using the relationship:
[tex]\[ \text{pH} + \text{pOH} = 14 \][/tex]
6. Substituting the calculated pOH value:
[tex]\[ \text{pH} = 14 - 5.187086643357144 \][/tex]
7. The calculated pH value is approximately:
[tex]\[ \text{pH} \approx 8.812913356642856 \][/tex]

So, the pH of the 6.50 x 10^-6 M KOH solution is approximately 8.8129.

---
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.