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\begin{tabular}{r|l|l}
Mountain View School & & Bay Side School \\
\hline
& 0 & [tex]$5,6,8$[/tex] \\
[tex]$9,8,2,0$[/tex] & 1 & [tex]$0,2,4,5,6,8$[/tex] \\
[tex]$8,7,6,5,5,4,4,3,1,0$[/tex] & 2 & [tex]$0,0,2,3,5$[/tex] \\
0 & 3 & \\
& 4 & 2
\end{tabular}

Key: 2|1|0 means 12 for Mountain View and 10 for Bay Side

Part A: Calculate the measures of center. Show all work. (2 points)

Part B: Calculate the measures of variability. Show all work. (1 point)

Part C: If you are interested in a larger class size, which school is a better choice for you? Explain your reasoning. (1 point)

Sagot :

To solve this problem, we will address each part step-by-step.

### Part A: Calculate the Measures of Center

Mean:
The mean (average) is calculated by summing all the values and dividing by the number of values.

For Mountain View School:
Sum of values \(= 9 + 8 + 2 + 0 + 8 + 7 + 6 + 5 + 5 + 4 + 4 + 3 + 1 + 0 = 62\)
Number of values \(= 14\)

[tex]\[ \text{Mean}_{\text{MV}} = \frac{62}{14} = 4.43 \][/tex]

For Bay Side School:
Sum of values \(= 5 + 6 + 8 + 0 + 2 + 4 + 5 + 6 + 8 + 0 + 0 + 2 + 3 + 5 + 2 = 56\)
Number of values \(= 15\)

[tex]\[ \text{Mean}_{\text{BS}} = \frac{56}{15} = 3.73 \][/tex]

Median:
The median is the middle number in a sorted list of numbers. If the number of observations is even, the median is the average of the two middle values.

For Mountain View School (sorted): \(0, 0, 0, 1, 2, 3, 4, 4, 5, 5, 6, 7, 8, 9\)
Since there are 14 values, the median is the average of the 7th and 8th values.

[tex]\[ \text{Median}_{\text{MV}} = \frac{4 + 4}{2} = 4.5 \][/tex]

For Bay Side School (sorted): \(0, 0, 0, 2, 2, 3, 4, 5, 5, 6, 6, 8, 8, 5, 2\)
There are 15 values, so the median is the 8th value.

[tex]\[ \text{Median}_{\text{BS}} = 4.0 \][/tex]

### Part B: Calculate the Measures of Variability

Standard Deviation:
The standard deviation measures how spread out the numbers are from the mean.

For Mountain View School:
The values are \(9, 8, 2, 0, 8, 7, 6, 5, 5, 4, 4, 3, 1, 0\), and the mean is \(4.43\).

The standard deviation is calculated by the formula:
[tex]\[ s = \sqrt{\frac{1}{N-1} \sum_{i=1}^N (x_i - \overline{x})^2} \][/tex]
Where \(N\) is the number of values, \(x_i\) are the values, and \(\overline{x}\) is the mean.

[tex]\[ s_{\text{MV}} = 2.98 \][/tex]

For Bay Side School:
The values are \(5, 6, 8, 0, 2, 4, 5, 6, 8, 0, 0, 2, 3, 5, 2\), and the mean is \(3.73\).

[tex]\[ s_{\text{BS}} = 2.71 \][/tex]

### Part C: Determining the Better School for Larger Class Size

To determine which school is better for larger class size, we compare their means. The school with the higher mean has a tendency to have larger class sizes.

From our calculations:
- Mean of class sizes at Mountain View School: \(4.43\)
- Mean of class sizes at Bay Side School: \(3.73\)

Since Mountain View School has a higher mean class size than Bay Side School, Mountain View School is the better choice if you are interested in larger class sizes.

Conclusion:
Mountain View School is a better choice for larger class sizes, as it has a higher mean score (4.43) compared to Bay Side School's mean score (3.73).