Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Get immediate and reliable solutions to your questions from a knowledgeable community of professionals on our platform. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform.
Sagot :
Answer:
18V
Explanation:
When two resistors R1 and R2 are arranged in parallel then the effective/ total resistance
[tex] \frac{1}{ \: \:R_{ \:T}} = \frac{1}{ \ \: R_{1} } + \frac{1}{ \ \: R_{2} } [/tex]
[tex]\frac{1}{ \: \:R_{ \:T}} = \frac{1}{30} + \frac{1}{60} [/tex]
[tex]\frac{1}{ \: \:R_{ \:T}} = \frac{2 + 1}{60} [/tex]
[tex]\frac{1}{ \: \:R_{ \:T}} = \frac{3}{60} = \frac{ 1}{20} [/tex]
[tex]R_{ \:T} = 20 \: ohms[/tex]
From Ohm's law,
V = IR,
since 0.60A current passes through the 30 ohms resistor then the voltage across the 30 ohms
= 0.60 × 30
= 18 V.
Given that the resistors are arranged in parallel then same voltage is across the two resistors that is,
Voltage across 60 ohms = voltage across 30 ohms.
Voltage across 60 ohms = 18V
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.